What is one type of disease that is caused by a dominant allele

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Huntington’s disease is a disorder of the nervous system that is caused by a dominant allele. Thanks for ChaChaing! [ Source: http://www.chacha.com/question/what-is-one-type-of-disease-that-is-caused-by-a-dominant-allele ]
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What is one type of disease that is caused by a dominant allele?
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Huntington’s disease is a disorder of the nervous system that is caused by a dominant allele. Thanks for ChaChaing!

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biology test help???????
Q: Please help me with this biology test! Please no fake answers,i really need help with this. 10pts who help me!3. A type of chromosome change that involves reversing a fragment of the original chromosome isA. a duplication.B. a deletion.C. an inversion.D.a translocation.4. Down syndrome is also known as Trisomy 21 because people haveA. two copies of chromosome 21.B.one copy of chromosome 21.C.four copies of chromosome 21.D. three copies of chromosome 21.5. During which phase is nondisjunction likely to occur?A. ProphaseB. MetaphaseC. AnaphaseD. Telophase7. Identifying genes will aid inA. diagnosing common ailments.B. treating common ailments.C. preventing common ailments.D. all of the above.8. Lethan dominant alleles are less common than lethan recessive alleles becauseA. lethan recessive alleles usually have a large effect on carriers.B. most people with dominant disorders die before producing offspring.C. lethan dominant alleles cannot be caused by a natural mutation.D. none of the above.Small proteins that the DNA are wrapped around are called…A. enzymes.B. histones.C. DNA polymerase.D. helicase.The event in which homologous chromosomes or sister chromatids fail to separate during meiosis is calledA. nondisjunction.B. duplication.C. deletion.D. translocation.. The sex-linked allele for colorblindness is located onA. chromosome 21.B. the X chromosome only.C. the Y chromosome only.D. both the X chromosome and the Y chromosomeWhat type of effect would you expect large deletions to have on the body?A. Little to no effect.B. Some effect.C. Serious effect.13. Which of the following is caused by a dominant allele?A. Huntington’s diseaseB. albinismC. cystic fibrosisD.none of the above14. Which of the following statements is NOT true?A.A person with Huntington’s disease might not pass the allele for the disease to his or her offspring.B. A person with Huntington’s disease might be homozyous for the disease.C. Huntington’s disease is caused by a recessive allele.D. A person who inherits one allele for Huntington’s disease will develop the disease.15. Which of the following would you be least likely to see in a pedigree?A. All of the symbols are unshaded.B. All of the symbols are shaded.C. All of the symbols are half-shaded.D. About half of the symbols are circles.16. A pedigree showing the inheritance of Huntington’s disease within a family WOULD NOT show any half-shaded symbols.A. TrueB. False17. In a pedigree for a recessive trait, if a mother is represented by a shaded circle and a father is represented by a shaded square, their children cannot be represented by HALF-SHADED circles or squares.A. TrueB. False18. Two parents who have Huntington’s disease MAY produce an offspring who does not have Huntington’s disease.A. TrueB. False19. Cancer occurs from a single mutation.A. TrueB. False20. Tumor-suppressor genes make proteins called growth factors.A. TrueB. False21. Growth factors are proteins that initiate cell division.A. TrueB. False22. Cancer can be inherited.A. TrueB. False23. Cancer is a genetic disease.A. TrueB. False24. If an individual inherits a mutated tumor-suppressor gene (i.e. BRCA1) they will DEFINITELY develop cancer.A. TrueB. False25. If a person develops skin cancer they do NOT have to worry about passing it to their offspring because the mutations are in the skin cells not in the gametes.A. TrueB. False
A: 3) C. inversion4) D. three copies5) D. Telophase.. i think. nondisjunction is failure to separate during meiosis I or II, telophase is the last part of cell division7) A. diagnosing, you can’t necessarily treat something based off the gene8) D. i don’t believe there is a reason for that one.9) A. almost all enzymes are proteins, C and D are both proteins, B has nothing to do with it.10) A. nondisjunction11) B. X chromosome12)C. large deletions can alter the whole order of the genes which can change the amino acids being made13) A. huntingtons disease14) B. homozygous means both are the same, they will obviously have the disease if both jeans are positive.15)A. that would mean everyone is homozygous for that trait, very infrequent16)B17)B18)A19)B i think this is false, not positive though20)A i think this is true.21)A22)A23)B???24)B25)i think B, but it depends, certain cancers are genetic.These questions are difficult because it can be both ways.hope this helps
GENETICS PROBLEM, CAN SOMEBODY SHOW ME HOW TO SOLVE THESE PROBLEMS, HELP ME PLEASE!!!!!!!?
Q: Simple Monohybrid Cross—this type of cross involves a single trait controlled by a single pair of alleles. One allele is dominant and the other is recessive.Phenylketonuria—Individuals with this disorder are unable to produce the enzyme responsible for the conversion of the amino acid phenylalanine to the amino acid tyrosine. Because tyrosine is needed in the production of melanin, PKU sufferers are light-haired and fair –skinned. Phenylalanine is present in protein and in the artificial sweetener aspartamine (such as Equal). Phenylalanine builds up in the body and acts as a neurotoxin causing brain damage and mental retardation. Most states require that all newborns be tested for the presence of this disorder. Afflicted individuals are placed on a special diet that is extremely low in phenylalanine. Strict adherence to this diet can prevent the brain damage and mental retardation. As a result of early detection and treatment, adults with this disorder may have a normal phenotype. PKU is caused by a recessive allele (p). Therefore, only individuals homozygous for the allele will develop the disorder.Assume a man homozygous for PKU marries a woman who is heterozygous for PKU and answer the following questions.1-what is the genotype of the man?2-what is the genotype of the woman?3-What is the probability that their chid will have PKU?4-What would be the genotype of the child has PKU?5-What is the probability that thier child would be a carrier (carries one recessive allele but does not have the disease)?6-What would be the genotype of the child if he/she was a carrier?Huntington Disease—Individuals with Huntington disease have massive degeneration of the basal nuclei in the brain leading to wild involuntary movements and progressing to dementia and death. This disease is caused by repeats of the CAG codons near the end of chromosome 4. One in 24,000 individuals develops the disorder. It is caused by a dominant allele so that every individual who inherits the allele will eventually develop the disease. Symptoms do not usually appear until after the age of 30. Huntington Disease is lethal to the embryo in the homozygous condition (HH).Using the following information, answer the questions below. A couple has been married for five years and are pregnant with their first child when they learn that the man’s father has Huntington Disease. Assume that both the man’s wife and his mother are genotypically normal. No HD has been noted in the wife’s family. Let the dominant allele for Huntington = H. Using a Punnett square and your formulas for probability will help you solve the problems.1-what is the man’s father’s genotype?2-What is the wife;s genotype?3-What would the man’s genotype be it he has inherited the disease from his father?4-What is the probability that the man has inherited the disease from his father?5-What is the probability that the couple will have a child with Huntington Disease IF the man has inherited the disease?6-With the information currently available (all probabilities), what is the probaility that the couple will have a child with Huntington disease? Remember that you have two probabilities to consider, one is “if” the man has inherited the disease, and two “if” he has, then what is the probability of the child inheriting the disease.7-Why do you think Huntington disease can not be eliminated by natural selection?
A: For Phenylketonuria case, A man homozygous for PKU marries a woman who is heterozygous for PKU. U have to imgine the symbol first before do the punnet square. The symbol for the man is pp and the woman is Pp. By visualizing the symbol, u have already answered the no. 1 & 2. Now, do the punnet square:pp x Pp = Pp, pp, Pp and ppmeans that 50% Pp (heterozygous for PKU) –> this is the answer for no.5 & 6and 50% pp (homozygous for PKU) –> this is the answer for no.3 and 4 It’s easy, right?
Balanced Polymorphism and Evolution?
Q: A student happened to be walking along a lake in central Florida. She noticed a small school of minnows swimming in the shallow water near the shoreline. Upon closer examination she noted that all of these minnows were silver colored, with the exception of one. That one was mostly black and white. Later she mentioned this to her AP Biology teacher. He said that this was an example of balanced polymorphism. Balance polymorphism is an evolutionary event in which one morph has improved chances of survival if it exists in very small frequencies. This condition is called: Heterozygote advantage Stabilizing selection Diversifying selection Homozygous advantage Frequency-dependent selectionThe Heliconius butterfly deposits eggs on the Passion Flower vine. However, the caterpillars are extremely voracious consumers. As a consequence the butterfly will not deposit eggs on a vine that already contains Heliconius eggs. The vines frequently have pigmented areas that mimic eggs. This restricts the number of eggs laid on the vine. This is an example of: Convergent evolution Divergent evolution Coevolution Diversifying selection None of the aboveAllopatric speciation and sympatric speciation are two mechanisms of speciation Allopatric speciation is most closely associated with which of the following? isolation and a small population formation of fertile hybrids requires more than one generation formation of a new species without geographic separation Choices 1 and 3Natural selection has the potential to reduce the number and types of variations within a population. How is this potential removal of variations countered? frequency-dependent selection heterozygote advantage diploidy balancing selection all of the above ensure that variations, even potentially harmful ones, will be maintained within a populationWhat portion of a large population of individuals will be carriers of PKU (a human genetic disease caused by a recessive allele) if 9% of the population has the disease? 91% 30% 42% 49% 0%In a population of rabbits, white fur is caused by the recessive allele g, and the dominant gray by G. If 36% of the population express the homozygous recessive white condition, what is the frequency of the dominant allele, G, in that population? .64 .06 .60 .04 .40
A: 1) Frequency-dependent selection2)Coevolution3)Choices 1 and 34)all of the above ensure that variations, even potentially harmful ones, will be maintained within a population5) 42%6)0.4
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